Fluid MechanicsMedium
Question
A cubical block of wood of edge 10cm and mass 0.92 kg floats on a tank of water with oil of rel. density 0.6. Thickness of oil is 4cm above water. When the block attains equilibrium with four of its sides edges vertical :
Options
A.1 cm of it will be above the free surface of oil.
B.5 cm of it will be under water.
C.2 cm of it will be above the common surface of oil and water.
D.8 cm of it will be under water.
Solution
Let completely submerged in water, then
Fb = 1000 > mg(920) So, not possible
Let complete in oil
Fb = (0.6) (4) (1000 + (1) (6) (100) = 840
Fb < mg So, not possible
So, let ′X′ part in oil and remaining in water
920 = [(1) (10 − x) + (0.6) (x)] 100
9.2 = 10 − x + 0.6 x
0.4 x = 0.8
x = 2 cm.
Fb = 1000 > mg(920) So, not possible
Let complete in oil
Fb = (0.6) (4) (1000 + (1) (6) (100) = 840
Fb < mg So, not possible
So, let ′X′ part in oil and remaining in water
920 = [(1) (10 − x) + (0.6) (x)] 100
9.2 = 10 − x + 0.6 x
0.4 x = 0.8
x = 2 cm.
Create a free account to view solution
View Solution FreeMore Fluid Mechanics Questions
A small sphere of radius 'r' falls from rest in a viscous liquid. As a result, heat is produced due to viscous f...A glass capillary tube is of the shape of a truncated cone with an apex angle α so that its two ends have cross sec...Water flows in a streamline motion through a horizontal pipe of circular cross-section as shown in the figure. The press...A metallic sphere floats in an immiscible mixture of water (ρw = 103 kg/m3) and a liquid (ρL = 13.5 × 103...A ball is made of a material of density ρ where ρoil water with ρoil and ρwater representing the den...