Fluid MechanicsHard
Question
A cubical block of wood of edge 10cm and mass 0.92 kg floats on a tank of water with oil of rel. density 0.6. Thickness of oil is 4cm above water. When the block attains equilibrium with four of its sides edges vertical :
Options
A.1 cm of it will be above the free surface of oil.
B.5 cm of it will be under water.
C.2 cm of it will be above the common surface of oil and water.
D.8 cm of it will be under water.
Solution
Let completely submerged in water, then
Fb = 1000 > mg(920) So, not possible
Let complete in oil
Fb = (0.6) (4) (1000 + (1) (6) (100) = 840
Fb < mg So, not possible
So, let ′X′ part in oil and remaining in water
920 = [(1) (10 − x) + (0.6) (x)] 100
9.2 = 10 − x + 0.6 x
0.4 x = 0.8
x = 2 cm.
Fb = 1000 > mg(920) So, not possible
Let complete in oil
Fb = (0.6) (4) (1000 + (1) (6) (100) = 840
Fb < mg So, not possible
So, let ′X′ part in oil and remaining in water
920 = [(1) (10 − x) + (0.6) (x)] 100
9.2 = 10 − x + 0.6 x
0.4 x = 0.8
x = 2 cm.
Create a free account to view solution
View Solution FreeMore Fluid Mechanics Questions
At which temperature, surface tension of water will be minimum -...The height to which water rises in a capillary will be -...A spherical body of radius R consists of a fluid of constant density and is in equilibrium under itsown gravity. If P(r)...If the difference between pressure inside and outside of a soap bubble is 6 mm of water and its radius is 8 mm. What is ...Which one of the following would a hydrogen balloon find easiest to lift :-...