Fluid MechanicsHard
Question
A uniform rod OB of length 1m, cross-sectional area 0.012 m2 and relative density 2.0 is free to rotate about O in vertical plane. The rod is held with a horizontal string AB which can withstand a maximum tension of 45 N. The rod and string system is kept in water as shown in figure. The maximum value of angle α which the rod can make with vertical without breaking the string is
Options
A.45o
B.37o
C.53o
D.60o
Solution
F.B.D. of rod NM+ dk F.B.D. :
W = (0.012) (1) (2 × 103) (10) = 240 N
Fb = (0.012) (1) (103) (10) = 120 N
Torque about O
(For equilibrium)
(240 − 120)
= 45 (cos α) ⇒ = 
= 
⇒ α = 37o
W = (0.012) (1) (2 × 103) (10) = 240 N
Fb = (0.012) (1) (103) (10) = 120 N
Torque about O
(For equilibrium)
(240 − 120)
= 45 (cos α) ⇒ = = ⇒ α = 37oCreate a free account to view solution
View Solution FreeMore Fluid Mechanics Questions
In a hydraulic lift, used at a service station the radius of the large and small piston are in the ratio of 20 : 1. What...Sudden fall of atmospheric pressure by a large amount indicate...A spherical body of radius R consists of a fluid of constant density and is in equilibrium under itsown gravity. If P(r)...Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6...Internal radius of a capilary tube is cm and surface tension of water 70 dyne/cm, if angle of contact is zero, then wate...