ProbabilityHard
Question
There are 4 urns. The first urn contains 1 white & 1 black ball, the second urn contains 2 white & 3 black balls, the third urn contains 3 white & 5 black balls & the fourth urn contains 4 white & 7 black balls. The selection of each urn is not equally likely. The probability of selecting ith urn is 
(i = 1, 2, 3, 4). If we randomly select one of the urns & draw a ball, then the probability of ball being white is :
(i = 1, 2, 3, 4). If we randomly select one of the urns & draw a ball, then the probability of ball being white is :Options
A.
B.
C.
D.none of these
Solution
U1 - 1W + 1B U2 → 2W + 3B
U3 → 3W + 5B U4 → 4W + 7B
P(W) =
(u1) P(w/ui) = 
P(w/vi)
=
U3 → 3W + 5B U4 → 4W + 7B
P(W) =
(u1) P(w/ui) = P(w/vi)=
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