ProbabilityHard
Question
A 9 digit number using the digits 1, 2, 3, 4, 5, 6, 7, 8 & 9 is written randomly without repetetion. The probability that the number will be divisible by 9 is:
Options
A.1/9
B.1/2
C.1
D.9!/99
Solution
Since sum of 1 + 12 + 3 +......9 =
= 45 is disisible by 9, hance all no. will be divisible by 9.
Create a free account to view solution
View Solution FreeMore Probability Questions
Let 0 < P (A) < 1, 0 < P (B) < 1 and P(A υ B) = P (A) + P (B) - P (A) P (B). Then -...If a, b and c are three numbers (not necessarily different) chosen randomly and with replacement from the set {1, 2, 3, ...A man alternately tosses a coin and throws a dice beginning with the coin. The probability that he gets a head in the co...If A and B be any two events, then P (AB) equals-...A fair die is thrown twenty times. The probability that on the tenth throw the fourth six appears is-...