Fluid MechanicsHard
Question
There are two identical small holes on the opposite sides of a tank containing a liquid. The tank is open at the top. The difference in height of the two holes is h as shown in the figure. As the liquid comes out of the two holes, the tank will experience a net horizontal force proportional to:
Options
A.h1/2
B.h
C.h3/2
D.h2
Solution
Fthrust = ρav2
Fnet = F1 − F2 = aρ[2g(h1 − h2)]
= aρ(2gh)
or F ∝ h
Fnet = F1 − F2 = aρ[2g(h1 − h2)]
= aρ(2gh)
or F ∝ h
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