Permutation and CombinationHard
Question
The number of ways in which 10 students can be divided into three teams, one containing 4 and others 3 each, is
Options
A.
B.2100
C.10C4 . 5C3
D.
Solution
Total required number of teams is
= 10C4 . 5C2 = 2100
= 10C4 . 5C2 = 2100
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