Permutation and CombinationHard
Question
The number of ways in which 5 X′s can be placed in the squares of the figure so that no row remains empty is:
Options
A.97
B.44
C.100
D.126
Solution
Total number is 8C5 = 56
not required is 6C5 + 6C5 = 12
Hence required no of arrangement = 56 - 12 = 44
not required is 6C5 + 6C5 = 12
Hence required no of arrangement = 56 - 12 = 44
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