Permutation and CombinationHard
Question
Seven different coins are to be divided amongst three persons. If no two of the persons receive the same number of coins but each receives atleast one coin & none is left over, then the number of ways in which the division may be made is:
Options
A.420
B.630
C.710
D.none
Solution
Coin dividing in any are possible i.e.
1, 2, 4
so the number of ways is
7C1 . 6C2 . 4C4 . 3! = 7 × 15 × 6 = 630
1, 2, 4
so the number of ways is
7C1 . 6C2 . 4C4 . 3! = 7 × 15 × 6 = 630
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