Permutation and CombinationHard
Question
Seven different coins are to be divided amongst three persons. If no two of the persons receive the same number of coins but each receives atleast one coin & none is left over, then the number of ways in which the division may be made is:
Options
A.420
B.630
C.710
D.none
Solution
Coin dividing in any are possible i.e.
1, 2, 4
so the number of ways is
7C1 . 6C2 . 4C4 . 3! = 7 × 15 × 6 = 630
1, 2, 4
so the number of ways is
7C1 . 6C2 . 4C4 . 3! = 7 × 15 × 6 = 630
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
nPn is equal to-...The number of ways in which 8 different flowers can be strung to form a garland so that 4 particulars flowers are never ...There are 20 persons among whom two are brothers. The number of ways in which we can arrange them round a circle so that...The number of words formed with the letters of the word ′JODHPUR′ in which P,U, R never come together, is-...How many four digit numbers from the digits 0,1, 2, 3 will contain 3 at unit place (Rept. not allowed)...