Permutation and CombinationHard
Question
There are 12 points in a plane of which 5 are collinear. The number of distinct quadrilaterals which can be formed with vertices at these points is:
Options
A.2. 7P3
B.7P3
C.10 7C3
D.420
Solution
Total number of required quadrilateral
7C4 + 7C3 × 5C1 + 7C2 × 5C2
= 35 + 175 + 210 = 420 = 2 .7p3
7C4 + 7C3 × 5C1 + 7C2 × 5C2
= 35 + 175 + 210 = 420 = 2 .7p3
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