Permutation and CombinationHard
Question
A box contains 2 white balls, 3 black balls & 4 red balls. In how many ways can three balls be drawn from the box if atleast one black ball is to be included in draw (the balls of the same colour are different).
Options
A.60
B.64
C.56
D.none
Solution
First we find 3 ball from 9 ball
9C3 = 84
Now number of ways if any one black ball not selected is 6C3 = 20
Here required no is 84 - 20 = 64
9C3 = 84
Now number of ways if any one black ball not selected is 6C3 = 20
Here required no is 84 - 20 = 64
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
The number of ways to make 5 heaps of 3-3 books each from 15 different books a-...The number of words which can be formed from the letters of the word ′BHARATPUR′ so that P,U,R always remain...The number of ways in which n prizes can be distributed among n students when each student is eligible to get any number...How many 4 digit numbers can be formed with digits 1, 2, 3, 4, 5 when digits may be repeated ?...The number of rectangles in the adjoining figure is -...