Permutation and CombinationHard
Question
A box contains 2 white balls, 3 black balls & 4 red balls. In how many ways can three balls be drawn from the box if atleast one black ball is to be included in draw (the balls of the same colour are different).
Options
A.60
B.64
C.56
D.none
Solution
First we find 3 ball from 9 ball
9C3 = 84
Now number of ways if any one black ball not selected is 6C3 = 20
Here required no is 84 - 20 = 64
9C3 = 84
Now number of ways if any one black ball not selected is 6C3 = 20
Here required no is 84 - 20 = 64
Create a free account to view solution
View Solution FreeMore Permutation and Combination Questions
How many words can be formed from the letters of the word ′BHOPAL′ -...In a hockey series between team X and Y, they decide to play till a team win ′m′ match. Then the no. of ways...If function f(x) = , (fof) (√4)...In a library there are p copies of each n different books. The number of ways of selecting of one or more books from the...You are given 8 balls of different colour (black, white,...). The number of ways in which these balls can be arranged in...