Permutation and CombinationHard
Question
In an examination, a candidate is required to pass in all the four subjects he is studying. The number of ways in which he can fail is
Options
A.4P1 + 4P2 + 4P3 + 4P4
B.44 - 1
C.24 - 1
D.4C1 + 4C2 + 4C3 + 4C4
Solution
Number of ways he can fail is either one or two, three or four subject then total of ways.
4C1 + 4C2 + 4C3 + 4C4 = 24 - 1
4C1 + 4C2 + 4C3 + 4C4 = 24 - 1
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