Permutation and CombinationHard

Question

In an examination, a candidate is required to pass in all the four subjects he is studying. The number of ways in which he can fail is

Options

A.4P1 + 4P2 + 4P3 + 4P4
B.44 - 1
C.24 - 1
D.4C1 + 4C2 + 4C3 + 4C4

Solution

Number of ways he can fail is either one or two, three or four subject then total of ways.
4C1 + 4C2 + 4C3 + 4C4 = 24 - 1

Create a free account to view solution

View Solution Free
Topic: Permutation and Combination·Practice all Permutation and Combination questions

More Permutation and Combination Questions

Number of ways of placing 5 identical balls in 3 different boxes (no box remain empty), is -...Consider all the permutations of the word CORRUPTION. Number of words in which U appears prior to both R is equal to -...The number of ways of arranging the letters AAAAA, BBB, CCC, D, EE & F in a row if no two ′C′s are together ...Eleven animals of a circus have to be placed in eleven cages, one in each cage. If four of the cages are too small for s...A 5 digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 & 5 without repetition. The total numbe...