Permutation and CombinationHard
Question
5 boys & 3 girls are sitting in a row of 8 seats. Number of ways in which they can be seated so that not all the girls sit side by side, is:
Options
A.36000
B.9080
C.3960
D.11600
Solution
Total no. of arrangement if all the girls do not seat
side by side is
= [all arrangement - girls seat side by side]
= 8! - (6! × 3!) = 6! (56 - 6) = 6! × 50
= 720 × 50 = 36000
side by side is
= [all arrangement - girls seat side by side]
= 8! - (6! × 3!) = 6! (56 - 6) = 6! × 50
= 720 × 50 = 36000
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