ElectrostaticsHard
Question
Two smooth spherical non conducting shells each of radius R having uniformly distributed charge Q & - Q on their surfaces are released on a smooth non-conducting surface when the distance between their centres is 10 R. The mass of A is m and that of B is 2 m. The speed of A just before A and B collide is: [Neglect gravitational interaction]


Options
A.
B.
C.
D.
Solution
By conservation of momentum
m VA = 2m VB . ∴
= 
Also,
= 2 (where KA & KB are K.E. of A & B respectively)
from conservation of mechanical energy principle :
Ui + Ki = Uf + Kf or
+ = −
+ KA + KB
∴ KA + KB =
+
= 

KA +
=

KA =

KA =

or
mvA2 =
∴ VA = 
m VA = 2m VB . ∴
Also,
from conservation of mechanical energy principle :
Ui + Ki = Uf + Kf or
∴ KA + KB =
KA +
KA =
or
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
For a dipole, the value of each charge is 10−10 state coulomb and separation is 1, then its dipole moment is : -...A small electric dipole is of dipole moment p. The electric potential at a distance ′r′ from its centre and ...At distance of 5cm and 10cm outwards from the surface of a uniformly charged solid sphere, the potentials are 100V and 7...Three dipoles each of dipole moment of magnitude p are placed tangentially on a circle of radius R in its plane position...A charge is placed at a distance r from the axis of dipole. Force acting on it is F. If distance is made to double then ...