ElectrostaticsHard
Question
AB and CD are two large non parallel metallic plates connected to a battery as shown. If σA and σB be charge densities at points A and B respectively then :


Options
A.σA > σB
B.σA < σB
C.σA ≥ σB
D.σA ≤ σB
Solution
The potential in each of the plate remains same.

i.e. VAC = VBD ⇒ EAC × l1 = EBD × l2
⇒ EAC < EBD (as l1 > l2)
∴ σA < σB (since, E α σ)

i.e. VAC = VBD ⇒ EAC × l1 = EBD × l2
⇒ EAC < EBD (as l1 > l2)
∴ σA < σB (since, E α σ)
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
In a uniformly charged sphere of total chargeQ and radius R, the electric field E is plottedas a function of distance fr...At distance of 5 cm and 10 cm outwards from the surface of a uniformly charged solid sphere, the potentials are 100 V an...Fig. shows field lines of an electric field, the line spacing parallel to the page is same every where. If the magnitude...A parallel combination of 0.1 MΩ resistor and a 10μF capacitor is connected across 1.5 V source of negligible ...Two infinitely long parallel conducting plates having surface charge density +σ and -σ respectively, are sep...