ElectrostaticsHard
Question
Figure shows an electric line of force which curves along a circular arc. The magnitude of electric field intensity is same at all points on this curve and is equal to E. If the potential at A is V, then the potential at B is :
Options
A.V - ERθ
B.V - 2ER sin θ/2
C.V + ERθ
D.V + 2ER sin θ/2
Solution
(A) VA − VB = work done by electric field on + 1 coul. charge from A to B = E Rθ
∴ VB = VA − ERθ = V − ERθ
∴ VB = VA − ERθ = V − ERθ
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