DeterminantHard

Question

If = (x - y) (y - z) (z - x) , then:

Options

A.k = - 3

B.k = - 1

C.k = 1

D.k = 3

Solution

= x^ky^kz^k

= (x - y) (y - z) (z - x) (xy + zy + zx) x^ky^kz^k at k = - 1
= (x - y) (y - z) (z - x)

Create a free account to view solution

View Solution Free

Topic: Determinant·Practice all Determinant questions

More Determinant Questions

Let A, B, C be three 3 × 3 matrices with real entries. If BA + BC + AC = I and det(A + B) = 0 then value of det(A +...The number of values of k for which the system of equations (k + 1)x + 8y = 4k kx + (k + 3) y = 3k -1 has infinitely man...If A and B are two matrices such that AB = B and BA = A, then A2 + B2 =...The least value of the product xyz for which the determinant is non-negative is :...The existence of unique solution of the system x + y + z = b, 2x + 3y − z = 6, 5x − y + az = 10 depends on -...