DeterminantHard

Question

If = (x - y) (y - z) (z - x) , then:

Options

A.k = - 3

B.k = - 1

C.k = 1

D.k = 3

Solution

= x^ky^kz^k

= (x - y) (y - z) (z - x) (xy + zy + zx) x^ky^kz^k at k = - 1
= (x - y) (y - z) (z - x)

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