ElectrostaticsHard

Question

A charged particle ′q′ is shot from a large distance with speed  v  towards a fixed charged particle Q. It approaches Q upto a closest distance r and then returns. If q were given a speed ′2v′, the closest distance of approach would be :

Options

A.r
B.2r
C.r/2
D.r/4

Solution

Comparison can be shown as :
V → 2V     ⇒    k → 4k     ⇒    PEmax →   4PEmax     ⇒    r → r/4

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