ElectrostaticsHard
Question
A charged particle ′q′ is shot from a large distance with speed v towards a fixed charged particle Q. It approaches Q upto a closest distance r and then returns. If q were given a speed ′2v′, the closest distance of approach would be :
Options
A.r
B.2r
C.r/2
D.r/4
Solution
Comparison can be shown as :
V → 2V ⇒ k → 4k ⇒ PEmax → 4PEmax ⇒ r → r/4
V → 2V ⇒ k → 4k ⇒ PEmax → 4PEmax ⇒ r → r/4
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