DeterminantHard
Question
Let f(x) = 
then the maximum value of f(x) is
then the maximum value of f(x) isOptions
A.4
B.6
C.8
D.12
Solution
f(x) = 
Applying C1 → C1 + C2 + C3
= (2 + 4 sin2x)
R2 → R2 - R1, R3 → R3 - R1
= (2 + 4 sin2x)
f(x) = (2 + 4sin 2x)
f(x)max = 6
Applying C1 → C1 + C2 + C3
= (2 + 4 sin2x)
R2 → R2 - R1, R3 → R3 - R1
= (2 + 4 sin2x)
f(x) = (2 + 4sin 2x)
f(x)max = 6
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