DeterminantHard

Question

If the system of equations x + 2y + 3z = 4, x + py + 2z = 3, x + 4y + μz = 3 has an infinite number of solutions, then :

Options

A.p = 2, μ = 3
B.p = 2, μ = 4   
C.3 p = 2μ
D.p = 4, μ = 2

Solution

ᐃ =     ᐃx =
ᐃy =      ᐃz =
For infinite no. of solution ᐃ = ᐃx = ᐃy = ᐃz = 0  ⇒ μ = 2, p = 4

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