DeterminantHard
Question
If the system of equations x + 2y + 3z = 4, x + py + 2z = 3, x + 4y + μz = 3 has an infinite number of solutions, then :
Options
A.p = 2, μ = 3
B.p = 2, μ = 4
C.3 p = 2μ
D.p = 4, μ = 2
Solution
ᐃ = 
ᐃx = 
ᐃy =
ᐃz = 
For infinite no. of solution ᐃ = ᐃx = ᐃy = ᐃz = 0 ⇒ μ = 2, p = 4
ᐃx = ᐃy =
ᐃz = For infinite no. of solution ᐃ = ᐃx = ᐃy = ᐃz = 0 ⇒ μ = 2, p = 4
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