DeterminantHard
Question
If x, y, z ∈ R & ᐃ = 
= - 16 then value of x is
= - 16 then value of x isOptions
A.-2
B.-3
C.2
D.3
Solution
3ᐃ = 
= - 16
Applying R2 → R2 - 2R1 & R3 → R3 - 3R1
ᐃ =
= - 16
Applying R3 → R3 - R2
= - 16
Applying R2 → R2 - 3R1
= - 16
⇒ - 2x(x2 - 0) = - 16 → x3 = 8 ⇒ x = 2
= - 16Applying R2 → R2 - 2R1 & R3 → R3 - 3R1
ᐃ =
= - 16Applying R3 → R3 - R2
= - 16Applying R2 → R2 - 3R1
= - 16⇒ - 2x(x2 - 0) = - 16 → x3 = 8 ⇒ x = 2
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