ElectrostaticsHard
Question
A sphere of radius 1 cm has potential of 8000 V. The energy density near the surface of sphere will be:
Options
A.64 × 105 J/m3
B.8 × 103 J/m3
C.32 J/m3
D.2.83 J/m3
Solution
E = Field near sphere = 
= 8 × 105 V/m .
∴ Energy density
E2 = 
= 2.83 J/m3.
= 8 × 105 V/m .∴ Energy density
E2 = = 2.83 J/m3.Create a free account to view solution
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