ElectrostaticsHard
Question
A 5 coulomb charge experiences a constant force of 2000 N when moved between two points separated by a distance of 2 cm in a uniform electric field. The potential difference between these two points is:
Options
A.8 V
B.200 V
C.800 V
D.20,000 V
Solution
∵ E = 
∴ E = 
= 400 N/C
Potential difference, ᐃV = E. d = 400 ×
= 8V.
∴ E = = 400 N/CPotential difference, ᐃV = E. d = 400 ×
= 8V.Create a free account to view solution
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