ElectrostaticsHard
Question
Two equal negative charges -q each are fixed at the points (0, a) and (0, - a) on the y-axis .A positive charge Q is released from rest at the point (2a, 0) on the x-axis. The charge Q will :
Options
A.Execute simple harmonic motion about the origin
B.At origin velocity of particle is maximum.
C.Move to infinity
D.Execute oscillatory but not simple harmonic motion.
Solution
(i) From diagram, force on Q at general position x, is given by
Fnet = − 2F cos θ = −
(Towards origin)(ii) When charge moves from (2a, 0) to origin O, force keeps on acting on Q and becomes zero at O.
∴ Velocity of Q is max. at O.
∴ Velocity of Q is max. at O.
(iii) ∵ Motion is SHM for very small displacements. & 2a is not very small is motion is periodic but not SHM.
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
The electric potential in a region is by the relation V(x) = 4 + 5x2. If a dipole is placed at position (-1, 0) with dip...The electrostatic potential inside a charged spherical ball is given by φ = αρ2 + b where r is the distan...Two positively charged particles X and Y are initially far away from each other and at rest. X begins to move towards Y ...Two large vertical and parallel metal plates having a separation of 1 cm are connected to a DC voltagesource of potentia...An electron enters an electric field with its velocity in the direction of the electric lines of force then : -...