Complex NumbersHard
Question
If (1 + i)z = (1 - i)
then z is
then z is Options
A.t(1 - i), t ∈ R
B.t (1 + i), t ∈ R
C.
, t ∈ R+
, t ∈ R+ D.none of these
Solution
z = 
⇒ z = - i
⇒ x + iy = - y - ix
⇒ x = - y
so z = x - ix , x ∈ R ⇒ x (1 - i) or t(1 - i), t ∈ R.
⇒ z = - i ⇒ x + iy = - y - ix⇒ x = - y
so z = x - ix , x ∈ R ⇒ x (1 - i) or t(1 - i), t ∈ R.
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