Complex NumbersHard
Question
The equation of the radical axis of the two circles represented by the equations,
|z - 2| = 3 and |z - 2 - 3 i| = 4 on the complex plane is :
|z - 2| = 3 and |z - 2 - 3 i| = 4 on the complex plane is :
Options
A.3iz - 3i
- 2 = 0
B.3iz - 3i
+ 2 = 0
C.iz - i
+ 1 = 0
D.2iz - 2i
+ 3 = 0
Solution
S1 ≡ 
S2 ≡
radical axis = S1 - S2 = 0
3i
- 3iz - 2 = 0
3iz - 3i
+ 2 = 0
S2 ≡
radical axis = S1 - S2 = 0
3i
3iz - 3i
Create a free account to view solution
View Solution FreeMore Complex Numbers Questions
is equal to -...Let z be a complex number such that $|z - 6| = 5$ and $|z + 2 - 6i| = 5$.Then the value of $z^{3} + 3z^{2} - 15z + 141$ ...If z satisfies the inequality |z - 1 - 2i| ≤ 1, then...Points z1 & z2 are adjacent vertices of a regular octagon. The vertex z3 adjacent to z2 (z3 z1) can be represented by -...If z1 = , a ≠ 0 and z2 = , b ≠ 0 are such that z1 = then -...