Neural Control and CoordinationHard
Question
During the propagation of a nerve impulse, the action potential results from the movement of
Options
A.K+ ions from extracellular fluid to intracellular fluid
B.Na+ ions from intracellular fluid to extracellular fluid
C.K+ ions from intracellular fluid to extracellular fluid
D.Na+ ions from extracellular fluid to intracellular fluid
Solution
During the propagation of a nerve impulse when a stimulus of adequate strength is applied to a polarized membrane, the permeability of the membrane to Na+ is greatly increased at the point of stimulation. As a result the sodium ion channels permit the influx of Na+ by diffusion. since, there are more Na+ ions entering than leaving the electrical potential of the membrane changes from -70mV towards zero. At 0 mV the membrane is said to be depolarized. while the resting potential is determined largely by K+ ions the action potential is determined laegely by Na+ ions, Action potential is another nane of nerve impulse. The stimulated negatively charged point on the membrane sends out an electrical current to the positive point adjacent to it This local current causes the adjacent inner part of the membrane to reverse its potential from -70 mV to +30 mV.
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