Complex NumbersHard
Question
If 1, α1, α2, α3, α4 be the roots of x5 - 1 = 0, then find the value of 
(where ω is imaginary cube root of unity.)
(where ω is imaginary cube root of unity.) Options
A.ω
B.ω2
C.1
D.- 1
Solution
(z - 1) (z - α1) .........(z - α4) = z5 - 1
Put z = ω, z = ω2 and divide
=
= (ω + 1)2 = ω4 = ω
Put z = ω, z = ω2 and divide
=
= (ω + 1)2 = ω4 = ωCreate a free account to view solution
View Solution FreeMore Complex Numbers Questions
The square root of −7 + 24i is -...The real and imaginary parts of are-...If z = x + iy and w = (1 - iz) / (z - i), then |w| = 1 implies that, in the complex plane...If S be the set of real values of x satisfying the inequality 1 - log2 ≥ 0 , then S contains -...If 2 sin θ − 2i cos θ = 1 + i√3, then value of θ is-...