Complex NumbersHard
Question
The equation |z - i| + |z + i| = k, k > 0, can represent
Options
A.an ellipse if k > 2
B.line segment if k = 2
C.an ellipse if k = 5
D.line segment if k = 1
Solution
Put z = x + iy

if k > 2 ⇒ ellipse
if 0 < k < 2 ⇒ hyperbola
if k = 2 ⇒ x2 = 0
⇒ |y - 1| + |y + 1| = 2
⇒ -1 ≤ y ≤ 1
Hence z = x + iy lies on line segment joining - i and i
if k > 2 ⇒ ellipse
if 0 < k < 2 ⇒ hyperbola
if k = 2 ⇒ x2 = 0
⇒ |y - 1| + |y + 1| = 2
⇒ -1 ≤ y ≤ 1
Hence z = x + iy lies on line segment joining - i and i
Create a free account to view solution
View Solution FreeMore Complex Numbers Questions
If S be the set of real values of x satisfying the inequality 1 - log2 ≥ 0 , then S contains -...A point ′z′ moves on the curve | z - 4 - 3i | = 2 in an arg and plane. The maximum and minimum values of | z...(x + iy)1/3 = a + ib, then is equal to -...If arg (z)...Let$A = \{ z \in \mathbb{C}:|z - 2| \leq 4\}$ and$B = \{ z \in \mathbb{C}:|z - 2| + |z + 2| = 5\}$.Then the max $\left\{...