Binomial TheoremHard

Question

The sum is equal to :

Options

A. (2n - 1 - 1)
B.(2n - 1)
C.(2n-1 - 1)
D.none

Solution

+ .... +   [nC1 + nC2 + .... + nCn-1]    (multiply and divde by n!)
= [2n - 2] = (2n-1 - 1)

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