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Binomial Theorem
Binomial Theorem
Hard
Question
The sum
is equal to :
Options
A.
(2
n - 1
- 1)
B.
(2
n
- 1)
C.
(2
n-1
- 1)
D.
none
Solution
+ .... +
[
n
C
1
+
n
C
2
+ .... +
n
C
n-1
] (multiply and divde by n!)
=
[2
n
- 2] =
(2
n-1
- 1)
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Binomial Theorem
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