ElectroMagnetic InductionHard
Question
A circuit containing capacitors C1 and C2 as shown in the figure are in steady state with key K1 closed. At the instant t = 0, if K1 is opened and K2 is closed then the maximum current in the circuit will be :
Options
A.1 A
B.1/2 A
C.2 A
D.None of these
Solution
None of these 
= 
Li2 ; Q0 = CeqV = 
V = (20 ×10-6)
= 
(0.2 × 10-3) i2 ⇒ i = 1 A
= Li2 ; Q0 = CeqV = V = (20 ×10-6) = (0.2 × 10-3) i2 ⇒ i = 1 ACreate a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
Number of turns in primary coil of a transformer is 240. When input voltage is 20 volt, then output voltage is 2.5 volt....A current i = 3.36 (1 + 2t) × 10-2 A increases at a steady rate in a loop straight wire. A very small circuler loop...A magent is taken towards a coil : (a) rapidly (b) slowly Then the induced emf is:-...The mutual inductance of the two coils is 1.25 henry. In the first coil, the current changes at 80 amp/sec, the value of...Diamagnetic substance are :-...