ElectroMagnetic InductionMedium
Question
A very small circular loop of area 5 × 10-4 m2 and resistance 2 ohm is initially concentric and coplanar with a stationary loop of radius 0.1 m. If one ampere constant current is passed through the bigger loop and the smaller loop is rotated about its diameter with constant angular velocity w. The current induced (in ampere) in the smaller loop will be :
Options
A.
× 10-9 cosωt
× 10-9 cosωtB.πω× 10-9 sinωt
C. × 10-9 sinωt
× 10-9 sinωtD.πw × 10-9 sinωt
Solution
E = π × 10-9 ωsinωt
Also E = i × 2. ⇒ i =
× 10-9 sin ωt.
Also E = i × 2. ⇒ i =
× 10-9 sin ωt. Create a free account to view solution
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