ElectroMagnetic InductionHard
Question
A current flows through a rectangular solid conductor in the presence of uniform magnetic field B pointing out of the page as shown. Then the potential difference VP − VQ is equal to. (assume charge carriers in the conductor to be positively charged moving with a drift velocity of v)
Options
A.Bvb
B.−Bvb
C.Bvc
D.Bvc
Solution
| ε | = B lv where l is the edge perpendicular to both B and 
i.e.c.
∴ | ε | = B v c.
Now by right hand thumb rule magnetic force an a positive charge moving towards right is in down ward direction Hence end P will be positive.
∴ Vp − VQ is positive.
⇒ ε = + Bvc.
i.e.c. ∴ | ε | = B v c.
Now by right hand thumb rule magnetic force an a positive charge moving towards right is in down ward direction Hence end P will be positive.
∴ Vp − VQ is positive.
⇒ ε = + Bvc.
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