ElectroMagnetic InductionHard
Question
A magnetic field (B), uniform between two magnets can be determined measuring the induced voltage in the loop as it is pulled through the gap at uniform speed 20 m/sec. Size of magnet and coil is 2cm × 1cm ×2cm and 4cm × 6cm as shown in figure. The correct variation of induced emf with time is : (Assume at t = 0, the coil enters in the magnetic field) :
Options
A.
B.
C.
D.
Solution
E = 
= 
= Bbv = B × 2 × 10-2 × 20 = 0.40 B
ᐃt =
= 5 × 10-4 sec = 500 m sec
t =
= 3 × 10-3 sec = 3000 m sec
Ans. (A)
= = Bbv = B × 2 × 10-2 × 20 = 0.40 B
ᐃt =
= 5 × 10-4 sec = 500 m sect =
= 3 × 10-3 sec = 3000 m secAns. (A)
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