Binomial TheoremHard

Question

If the second term of the expansion is 14a^5/2, then the value of is:

Options

A.4

B.3

C.12

D.6

Solution

T₂ = ⁿC₁ (a^1/13)^n-1 (a^3/2) = 14a^5/2
⇒ n = 14
∴ = 4

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