Binomial TheoremHard

Question

If the second term of the expansion is 14a5/2, then the value of is:

Options

A.4
B.3
C.12
D.6

Solution

T2 = nC1 (a1/13)n-1 (a3/2) = 14a5/2
⇒  n = 14
∴  = 4

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