Binomial TheoremHard
Question
If the second term of the expansion
is 14a5/2, then the value of
is:
Options
A.4
B.3
C.12
D.6
Solution
T2 = nC1 (a1/13)n-1 (a3/2) = 14a5/2
⇒ n = 14
∴
= 4
⇒ n = 14
∴
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