ElectroMagnetic InductionHard
Question
In the circuit diagram shown
Options
A.time constant is L/R
B.time constant is 2L/R
C.steady state current in inductor is 2ε/R
D.steady state current in inductor is ε/R
Solution
Since the other resistance is attached parallel to the battery hence the time constant of the circuit will be L/R. At steady State the inductor offers zero resistance have hence at that time current in inductor will be E/R.
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