ElectroMagnetic InductionMedium
Question
When induced emf in inductor coil is 50% of its maximum value then stored energy in inductor coil in the given circuit will be : -
Options
A.2.5 mJ
B.5 mJ
C.15 mJ
D.20 mJ
Solution
E = 
LI2 E = L 
=
× 5 × 10-3 × (1)2
= 2.5 mJ.
LI2 E = L =
× 5 × 10-3 × (1)2= 2.5 mJ.
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