ElectroMagnetic InductionHard
Question
The battery shown in the figure is ideal. The values are e = 10 V, R = 5Ω, L = 2H . Initially the current in the inductor is zero. The current through the battery at t = 2s is
Options
A.12 A
B.7 A
C.3 A
D.3 A
Solution
I + I1 + I2
I1 = E/R
L
= E
I2 =
I = E/R +
I = 12A.
I1 = E/R
L
= EI2 =
I = E/R +
I = 12A.
Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in the figure...In a secondary coil of a stepup transformer : -...A long straight wire is placed along the axis of a circular ring of radius R. The mutual inductance of this system is...An emf induced in a coil, the linking magnetic flux...On reducing 2 ampere current in the primary to zero in 0.01 second, an emf of 1000 volts is induced in the Secondary coi...