ElectroMagnetic InductionMedium
Question
The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate a. Resistance per unit length of the loop is ρ. Then current in wire AB is (AB is one of the diameters)
The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate a. Resistance per unit length of the loop is ρ. Then current in wire AB is (AB is one of the diameters)
The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate a. Resistance per unit length of the loop is ρ. Then current in wire AB is (AB is one of the diameters)
Options
A.
from A to B
from A to BB. from B to A
from B to AC.
from B to A
from B to AD.Zero
Solution
The induced current in upper semicircular and lower semicircular will cancel each other in diameter (AB).
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