ElectroMagnetic InductionHard
Question
Two inductor coils of self inductance 3H and 6H respectively are connected with a resistance 10Ω and a battery 10 V as shown in figure. The ratio of total energy stored at steady state in the inductors to that of heat developed in resistance in 10 seconds at the steady state is(neglect mutual inductance between L1 and L2 ):
Options
A.
B.
C.
D.1
Solution
Leff = 2H
Energy stored in inductor =
LI2
=
× (2) × (1)2 = 1J.
Energy developed in resistance = I2RT = 12 × 10 × 10 = 100 J
Hence the required ratio is
Energy stored in inductor =
LI2=
× (2) × (1)2 = 1J.Energy developed in resistance = I2RT = 12 × 10 × 10 = 100 J
Hence the required ratio is
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