ElectroMagnetic InductionHard
Question
Two inductor coils of self inductance 3H and 6H respectively are connected with a resistance 10Ω and a battery 10 V as shown in figure. The ratio of total energy stored at steady state in the inductors to that of heat developed in resistance in 10 seconds at the steady state is(neglect mutual inductance between L1 and L2 ):
Options
A.
B.
C.
D.1
Solution
Leff = 2H
Energy stored in inductor =
LI2
=
× (2) × (1)2 = 1J.
Energy developed in resistance = I2RT = 12 × 10 × 10 = 100 J
Hence the required ratio is
Energy stored in inductor =
LI2=
× (2) × (1)2 = 1J.Energy developed in resistance = I2RT = 12 × 10 × 10 = 100 J
Hence the required ratio is
Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
The magnetic property inherent in all materials is...Loop A of radius (r << R) moves towards loop B with a constant velocity V in such a way that their planes are alwa...In the given figure if the magnetic field, which is perpendicular to the plane of the paper in the inward direction incr...Consider a metal ring kept on a horizontal plane. A bar magnet is held above the ring with its length along the axis of ...The volume susceptibility of a magnetic material is 30 × 10-4. Its relative permeability will be :-...