ElectroMagnetic InductionHard
Question
AB and CD are fixed conducting smooth rails placed in a vertical plane and joined by a constant current source at its upper end. PQ is a conducting rod which is free to slide on the rails. A horizontal uniform magnetic field exists in space as shown. If the rod PQ is released from rest then,
Options
A.The rod PQ may move downward with constant acceleration
B.The rod PQ may move upward with constant acceleration
C.The rod will move downward with decreasing acceleration and finally acquire a constant velocity
D.either A or B.either A or B.
Solution
It the magnitude of IA is very large such that force due to magnetic field on PQ exceeds its weight then it will move upwards otherwise it will move downwards.
Create a free account to view solution
View Solution FreeMore ElectroMagnetic Induction Questions
A coil of 10-2 H inductance carries a current I = 2sin (100t) A. When current is half of its maximum value, then at that...A time varying voltage V = 2t volt is applied across an ideal inductor of inductance L = 2H as shown in figure. Then sel...In fig. (a) and fig. (b) two air-cored solenoids P and Q have been shown. They are placed near each other. In fig. (a), ...The armature coil of dynamo is in motion. The generated induced emf varies and the number of magnetic lines of force als...In electromagnetic induction the induced e.m.f. in a coil is independent from : -...