DifferentiationHard
Question
A value of b for which the equations
x2 + bx - 1 = 0
x2 + x + b = 0,
have one root in common is
x2 + bx - 1 = 0
x2 + x + b = 0,
have one root in common is
Options
A.-√2
B.-i√3
C.i√5
D.√2
Solution
x2 + bx - 1 = 0
x2 + x + b = 0, .....(1)
Common root is
(b - 1) x - 1 - b = 0
⇒ x =
This value of x satisfies equation (1)
⇒
+ b = 0 ⇒ b = √3i, - √3i, 0.
x2 + x + b = 0, .....(1)
Common root is
(b - 1) x - 1 - b = 0
⇒ x =
This value of x satisfies equation (1)
⇒
+ b = 0 ⇒ b = √3i, - √3i, 0.Create a free account to view solution
View Solution FreeMore Differentiation Questions
If f(x - y), f(x).f(y) and f(x + y) are in A.P. ∀ x, y ∈ R and f(0) ≠ 0, if f(x) has continuous deriva...If y = , then the value of xy where = 0 is-...If y = tan-1 , -π/2 < x < π/2, tan x < 1, then equals-...The differential coefficient of tan−1 mx with respect to m is-...If y = log (xx), then dy/dx equals-...