Continuity and DifferentiabilityHard

Question

If y = cos^-1 (cos x), then at x = is equal to

Options

A.1

B.-1

C.1/√2

D.-1/√2

Solution

y = cos^-1 (cos x)
∵ x =

⇒ y = cos^-1 (cos (2π - x))
⇒ y = 2π - x
= - 1

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