Current Electricity and Electrical InstrumentHard
Question
A battery of emf E and internal resistance r is connected across a resistance R. Resistance R can be adjusted to any value greater than or equal to zero. A graph is plotted between the current (i) passing through the resistance and potential difference (V) across it. Select the correct alternative (s)
Options
A.internal resistance of the battery is 5Ω
B.emf of the battery is 10 V
C.maximum current which can be taken from the battery is 2 A
D.V-i graph can never be a straight line as shown in figure.
Solution
V = E − ir
from graph V = 10 − 5i ⇒ r = 5Ω, E = 10V
imax =
= 2 amp
from graph V = 10 − 5i ⇒ r = 5Ω, E = 10V
imax =
= 2 ampCreate a free account to view solution
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