Current Electricity and Electrical InstrumentMedium
Question
A battery of emf E and internal resistance r is connected across a resistance R. Resistance R can be adjusted to any value greater than or equal to zero. A graph is plotted between the current (i) passing through the resistance and potential difference (V) across it. Select the correct alternative (s)
Options
A.internal resistance of the battery is 5Ω
B.emf of the battery is 10 V
C.maximum current which can be taken from the battery is 2 A
D.V-i graph can never be a straight line as shown in figure.
Solution
V = E − ir
from graph V = 10 − 5i ⇒ r = 5Ω, E = 10V
imax =
= 2 amp
from graph V = 10 − 5i ⇒ r = 5Ω, E = 10V
imax =
= 2 ampCreate a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
Electroplating is not provided to be used for...The thermo e.m.f. of a thermo-couple is 25 μV/oC at room temperature. A galvanometer of 40 ohm resistance, capable ...The resistance of all the wires between any two adjacent dots is R. The equivalent resistance between A and B as shown i...In the potentiometer experiment if deflection in galvanometer is measured zero then current will become zero in : -...A galvanometer of resistance $100\Omega$ gives full scale deflection for a current of 1 mA . It is converted into an amm...