LimitsHard
Question
If f(x) = 
x - 1, then on the interval [0, π]
x - 1, then on the interval [0, π] Options
A.tan (f(x)) and 
are both continuous
are both continuousB.tan (f(x)) and 
are both discontinuous
are both discontinuousC.tan (f(x)) and f-1 (x) are both continuous
D.tan (f(x)) is continuous but 
is not.
is not.Solution
f(x) = 
x - 1 ∀ x ∈ [0, π]
which is not continous at x = 2
tanf(x) = tan
∵ x ∈ [0, π]
∴
⇒ tan f(x) is continuous in [0, π]
y = f-1 (x) = 2(1 + x), which is also continous in [0, π]
x - 1 ∀ x ∈ [0, π] which is not continous at x = 2 tanf(x) = tan
∵ x ∈ [0, π]∴
⇒ tan f(x) is continuous in [0, π]
y = f-1 (x) = 2(1 + x), which is also continous in [0, π]
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