LimitsHard
Question
Options
A.2n
B.2n + 1
C.2n - 1
D.does not exist
Solution
sinθ < θ < tan θ , θ ∈ 


; n ∈ N
L.H.L. =
= n - 1 + n = 2n - 1
R.H.L. =
= n - 1 + n = 2n - 1
∴ L.H.L. = R.H.L = 2n - 1
L.H.L. =
R.H.L. =
∴ L.H.L. = R.H.L = 2n - 1
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