Circular MotionHard
Question
A Toy cart attached to the end of an unstretched string of length a, when revolved moves on a smooth horizontal table in a circle of radius 2a with a time period T. Now the toy cart is speeded up until it moves in a circle of radius 3a with a period T′. If Hook′s law holds then (Assume no friction) :
Options
A.T′ =
T
B.T′ =
T
C.T′ =
T
D.T′ = T
Solution
F = kx, T1 = ka = mω2 2a ⇒ ω = 
Time period =
=
= T
T2 = 2ka = mω23a ⇒ ω =
Time period =
= T′
T′ =
T Ans.
Time period =
T2 = 2ka = mω23a ⇒ ω =
Time period =
T′ =
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
A man is standing at the edge of a circular plate which is rotating with a constant angular speed about a perpendicular ...A small block slides with velocity 0.5 on the horizontal frictionless surface as shown in the Figure. The block leaves t...For a particle in uniform circular motion the acceleration at a point P(R, θ ) on the circle of radius R is (here &...A spherically symmetric gravitational system of particles has a mass density ρ = where ρ0 is a constant. A tes...If a cyclist moving with a speed of 4.9 m/s on levelled road can take a sharp circular turn of radius 4m, them the coeff...