Circular MotionHard
Question
A boy whirls a stone in a horizontal circle 1.8 m above the ground by means of a string with radius 1.2 m. while whirling the stone string was horizontal, it breaks and stone flies off horizontally, striking the ground 9.1 m away. The centripetal acceleration during the circular motion was: (use g = 9.8 m/s2)
Options
A.94 m/s2
B.141 m/s2
C.188 m/s2
D.282 m/s2
Solution
The time taken to fall on ground =
velocity at time of string breaksv =
⇒ v = 9.1
Centripetal acceleration =
= 
= 187.856 = 188 m/s2Create a free account to view solution
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