Circular MotionHard

Question

A boy whirls a stone in a horizontal circle 1.8 m above the ground by means of a string with radius 1.2 m.  while whirling the stone string was horizontal, it breaks and stone flies off horizontally, striking the ground 9.1 m away. The centripetal acceleration during the circular motion was: (use g = 9.8 m/s2)

Options

A.94 m/s2
B.141 m/s2
C.188 m/s2
D.282 m/s2

Solution


The time taken to fall on ground = velocity at time of string breaks
v = ⇒ v = 9.1
Centripetal acceleration = = = 187.856 = 188 m/s2

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