Circular MotionHard
Question
A particle of mass m begins to slide down a fixed smooth sphere from the top. What is its tangential acceleration when it breaks off the sphere ?
Options
A.2g/3
B.√5g/3
C.g
D.g/3
Solution
at loose contact N = 0
mg cos θ =
........(1)from energy conservation
mgR(1 − cos q) =
mv2 ....(2)from (1) & (2)
cos θ =
⇒ sin θ = 
tangential acceleration = g sin θ =
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