Center of MassMedium
Question
In the above question the maximum power delivered by the agent in pulling up the rope is
Options
A.lgv
B.
C.λlgv + v3λ
D.
Solution
Fnet = 
(mv)
F−mg =
v + 0
F = mg + v
, (m = vtλ)
= vtλg + v2λ
P = Fv = v2 λgt + λv3
= vtλg + v2λ
P = Fv = v2 λgt + λv3, P ↑ as t ↑ so Pmax = v2λg
+ λv3 = lλgv + λv3
(mv)F−mg =
v + 0F = mg + v
, (m = vtλ)= vtλg + v2λ
P = Fv = v2 λgt + λv3
= vtλg + v2λ
P = Fv = v2 λgt + λv3, P ↑ as t ↑ so Pmax = v2λg
+ λv3 = lλgv + λv3Create a free account to view solution
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